Question 1155079
let two integers be {{{x}}} and {{{y}}}

if their  sum is {{{16}}}, we have

{{{x+y=16}}}.........solve for {{{x}}}

{{{x=16-y}}}......eq.1


 and if their difference is {{{-8}}}, we have

{{{x-y=-8}}}

{{{x=y-8}}}......eq.2


 and if their  differences is {{{8}}}, we have

{{{x-y=8}}}

{{{x=8+y}}}......eq.3


from eq.1 and eq.2 we have

{{{16-y=y-8}}}

{{{16+8=y+y}}}

{{{24=2y}}}

{{{y=12}}}

from eq.1 and eq.3 we have

{{{16-y=y+8}}}

{{{16-8=y+y}}}

{{{8=2y}}}

{{{y=4}}}

go to

{{{x=16-y}}}......eq.1, plug in {{{y=12}}}

{{{x=16-12}}}

{{{x=4}}}


go to

{{{x=16-y}}}......eq.1, plug in {{{y=4}}}

{{{x=16-4}}}

{{{x=12}}}


solutions: 

{{{x=4}}},{{{y=12}}}

or

{{{x=12}}},{{{y=4}}}


so, two integers are: {{{4}}} and {{{12}}}