<PRE><B>Question 1154917</B>
&lt;br&gt;
A) There are 3 balls in box 3; 1 of them is white:&lt;br&gt;
P(last ball drawn from box 3 is white) = 1/3.&lt;br&gt;
B) In the 3 boxes together, there are a total of 14 balls, of which 8 are white:&lt;br&gt;
P(last ball drawn (from any box) is white) = 8/14 = 4/7.&lt;br&gt;
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Note that I ignored the comma (&quot;,&quot;) in part A.  That makes the probability to be found simply the probability that the white ball is the last one drawn from box 3.&lt;br&gt;
If the question in part A had been written with two commas -- &lt;br&gt;
&quot;What is the probability that the last ball, drawn from box 3, is white?&quot;&lt;br&gt;
then that would be a different probability: the probability that the last ball drawn is white, AND THAT IT COMES FROM BOX 3.  That would of course be a different problem.&lt;br&gt;
The question as written, with the single comma, is grammatically incorrect and therefore open to different interpretations.&lt;br&gt;
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