Question 1154947


The first term is {{{0}}}; the second term is {{{3}}}. What is the eleventh term in the sequence

if the sequence is arithmetic 

difference between first term and the second term is {{{ d=3}}}

{{{a[1]=0}}}
{{{a[2]=3}}}

nth term formula will be:

{{{a[n]=a[1]+(n-1)*d}}}.......since {{{a[1]=0}}} and {{{d=3}}}

{{{a[n]=0+(n-1)*3}}}

{{{a[n]=(n-1)*3}}} where {{{n}}}={{{1}}},{{{2}}},{{{3}}},....


check the formula for given terms
{{{n=1}}}
{{{a[1]=(1-1)*3=0}}}->true

{{{n=2}}}, 
{{{a[2]=(2-1)*3=1*3=3}}}->true

then {{{11}}}th term will be:


{{{n=11}}}, 
{{{a[11]=(11-1)*3=10*3=30}}}