Question 106817
x^3-9x+x^2-9 I am supposed to factor this completely:
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How about this:
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Rearrange:
x^3 + x^2 - 9x - 9
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Group factoring
(x^3 + x^2) - (9x + 9);sign changes on the 9
:
x^2(x + 1) - 9(x + 1)
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Factor out (x+1) and you have:
(x + 1) (x^2 - 9)
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x^2 - 9 is the difference of squares
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(x + 1) (x - 3) (x + 3)
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