Question 1154882
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Hi  
Find the exact solution on [0,2pi): 
{{{tan^2(theta) + sqrt(3)tan(theta)=0}}}
{{{(tan(theta))(tan(theta) + sqrt(3))=0}}}
Agree:
{{{tan(theta)= 0}}}
{{{ green(theta = 0)}}} 0r {{{ green(theta = pi)}}}

{{{tan(theta) + sqrt(3) = 0}}}
{{{tan(theta) = -sqrt(3)}}}
{{{green(theta = (2/3)pi) }}} 0r {{{green(theta = (5/3)pi) }}}