Question 1154889


use a linear equation in the form  {{{y =mx+b}}} where {{{m}}} is a slope and {{{b}}} is {{{y}}}-intercept 

given points:

{{{x}}}-intercept of the equation: {{{-8}}}=> point ({{{-8}}},{{{0}}})
{{{y}}}-intercept of the equation: {{{6}}}=> point ({{{0}}},{{{6}}})=> {{{b=6}}}

find slope {{{m}}} using given points:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(6-0)/(0-(-8))}}}

{{{m=6/(0+8)}}}

{{{m=3/4}}}


go to

{{{y =mx+b}}}.......substitute {{{m}}} and {{{b}}}

{{{y =(3/4)x+6}}}


{{{ graph( 600, 600, -10, 10, -10, 10, (3/4)x+6) }}}