Question 1154883

use a linear equation in the form  {{{y =mx+b}}} where {{{m}}} is a slope and {{{b}}} is {{{y}}}-intercept 

given points:

{{{x}}}-intercept of the equation: {{{-2}}}=> point ({{{-2}}},{{{0}}})
{{{y}}}-intercept of the equation: {{{3}}}=> point ({{{0}}},{{{3}}})=> {{{b=3}}}

find slope {{{m}}} using given points:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(3-0)/(0-(-2))}}}

{{{m=3/(0+2)}}}

{{{m=3/2}}}


go to

{{{y =mx+b}}}.......substitute {{{m}}} and {{{b}}}

{{{y =(3/2)x+3}}}


{{{ graph( 600, 600, -10, 10, -10, 10, (3/2)x+3) }}}