Question 1154817
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I will use the grouping method


    x^3 - 2x^2 + 3x - 6 = (x^3 - 2x^2) + (3x - 6) = x^2*(x-2) + 3*(x-2) = (x-2)*(x^2+3).


The factors are (x-2) and (x^2+3).


One of them is from your list.
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