Question 1154744

let the two numbers be {{{x}}} (larger number) and {{{y}}} (smaller number)

if the sum of two numbers is eighteen, we have

 {{{x+y=18}}}........solve for {{{x}}}

 {{{x=18-y}}}......... eq.1


if the total of {{{three}}}{{{ times}}} the smaller and {{{twice}}} the larger is forty-four, we have


{{{2x+3y=44}}}........eq.2.....substitute {{{x}}} from eq.1

{{{2(18-y)+3y=44}}}....solve for {{{y}}}

{{{36-2y+3y=44}}}

{{{y=44-36}}}

{{{y=8}}}

go to

{{{x=18-y}}}......... eq.1,substitute {{{y}}}

{{{x=18-8}}}

{{{x=10}}}


the two numbers are  {{{10}}} and {{{8}}}