Question 106792
The sum of the roots of {{{ax^2+bx+c = 0}}} where a, b, and c are real non-zero constants.

The roots of this general quadratic equation are given by:
{{{x = (-b+sqrt(b^2-4ac))/2a}}} or {{{x = (-b-sqrt(b^2-4ac))/2a}}}
When we add these, we get:
{{{((-b/2a)+sqrt(b^2-4ac)/2a) + ((-b/2a)-sqrt(b^2-4ac)/2a) = (-b/2a)+(-b/2a)}}} = {{{2(-b/2a) = -b/a}}}