Question 1154601
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The perimeter of a rectangular outdoor patio is 58 ft. The length is 35ft. greater than the width. What are the dimensions of the patio?
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The perimeter of a rectangular outdoor patio is P ft. The length is K ft. greater than the width w. What are the dimensions of the patio?
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Dimensions w+K and w.

{{{(w+K)+w=P/2}}}
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{{{w+K+w=P/2}}}
{{{2w+K=P/2}}}
{{{2w=P/2-K}}}

{{{w=(P/2-K)(1/2)}}}

{{{w=P/4-K/2}}}
Substitute the given values and solve.


That should give {{{w=(58/4-35)=-20.5}}}----------NO GOOD! 


QUICK RETRY:
{{{w+35+w=58/2}}}

{{{2w+35=29}}}----------this makes no sense; w would be negative.


The problem description does not work.