Question 1154526
"my ten digit number is six times more than my ones" =>{{{6}}} is the only digit that can be {{{6}}} times a digit, and it is {{{6*1=6}}}.  
So {{{6}}} has to be the tens digit.

then, "one hundred digit is {{{8}}} less than the tens digit" which is {{{6}}}:=> no digit is {{{8}}}less than {{{6}}}


in case "six times more"  was mistake and you have "six more" , than solution is possible



let units digit be {{{x}}}

since we have digits from {{{0}}} to {{{9}}}, {{{x}}} is greater than or equal to {{{0}}} and less than or equal to{{{ 9}}}

tens digit is {{{6}}} more than units digit:{{{x+6}}}

 so

{{{x+6<=9}}}

{{{x <=9-6}}}

{{{x <=3}}}

hundreds digit is eight less than {{{x+6}}}:{{{x+6-8=x-2}}}

{{{x-2>=0}}}

{{{x>=2}}}


solutions:

{{{x>=2}}} & {{{x<=3}}}-> take first whole number which is {{{2}}}


 therefore 

if ones {{{x=2 }}} 
tens {{{x+6=8}}}
hundreds {{{x-2=0}}}=> number is {{{082}}} which{{{ is}}}{{{ not}}} a three digit number

if {{{x=3}}}, 
tens digit is {{{3+6=9}}} and  
hundreds digit is {{{3+6-8=1}}}

=> a three digit number is {{{193}}}