Question 1154519
{{{drawing ( 600, 600, -10, 10, -10, 10,

green(line(2,6,7,6)),green(line(2,6,0,0)),green(line(9,0,7,6)),green(line(2,6,4,0)),locate(2,6.5,F),locate(7,6.5,R),locate(4,-0.5,D),locate(9,-0.5,E), 
locate(0.3,-0.5,A),locate(6,5.5,124), locate(4,0.5,124),locate(3,0.7,56),
locate(0.5,0.7,56),
graph( 600, 600, -10, 10, -10, 10, 0)) }}}


If {{{m}}} < {{{R = 124}}}°, what is {{{m}}} < {{{AFD}}}?

{{{m}}} < {{{R = 124}}}°,  measure of its opposite angle is same, so {{{m}}} ∠ {{{D = 124}}}°

triangle {{{AFD}}} lies between parallel lines, so sides {{{AF }}}and {{{FD}}} are equal in length

since  {{{m}}} <{{{D = 124}}}°  and{{{ AF=FD}}},  measure of angles at {{{A }}}and {{{D}}} in triangle {{{AFD}}} are {{{180-124=56}}}°

so,  
{{{m}}}<{{{AFD=180-(56+56)}}}
{{{m}}}<{{{AFD=180-112}}}
{{{m}}}<{{{AFD=68}}}°