Question 1154460
{{{ h(t) = -4.9t^2 + 16t + 14 }}}
When the equation has the form:
{{{ y = a*x^2 + b*x + c }}}, then
the formula for the t -value of the vertex 
( max or min )
is:
{{{ t[max] = -b/(2a) }}}
{{{ a = -4.9 }}}
{{{ b = 16 }}}
{{{ t[max] = -16 / ( 2*(-4.9 )) }}}
{{{ t[max] = 1.63265 }}} sec
It takes 1.633 sec to reach maximum height
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Here's the plot:
{{{ graph( 400, 400, -2, 6, -10, 30, -4.9x^2 + 16x + 14 ) }}}
check:
{{{ h[max] = -4.9*1.633^2 + 16*1.633 + 14 }}}
{{{ h[max] = -13.067 + 26.128 + 14  }}}
{{{ h[max] = 27.061 }}} m
This looks close on plot
OK