Question 1154445


if the length of the base of a triangle {{{a}}} is twice it's perpendicular height {{{h}}}, we have

{{{a=2h}}}.......eq.1

and if it's area is {{{36cm^2}}}, we have

{{{(1/2)a*h=36}}}.......eq.2

substitute {{{a}}} from eq.1

{{{(1/2)2h*h=36}}}

{{{(1/cross(2))cross(2)h^2=36}}}

{{{h^2=36}}}

{{{h=6}}}

go to

{{{a=2h}}}.......eq.1, substitute {{{h}}}

{{{a=2*6}}}

{{{a=12}}}


answer: it's length is {{{12}}} and perpendicular height is  {{{6}}}