Question 1154317

Find the area of the polygons whose vertices are:
a. (-4, 2), (3, -4), (6, 2), (1, 4)
b. (-3, 4), (1, 5), (4, 2), (3, -3), (-2, -4)
<pre>Area of the polygon = {{{1/2}}} the POSITIVE difference of the SUM of the POSITIVE and NEGATIVE DIAGONAL-PRODUCTS.
First of all, you have to make sure that the points have been aligned in a CLOCKWISE or COUNTERCLOCKWISE position. 
Sum of POSITIVE DIAGONAL-PRODUCTS: - 32
Sum of NEGATIVE DIAGONAL-PRODUCTS: 48
{{{highlight_green(matrix(1,9, Area, "=", (1/2) * (48 -  - 32), "=", (1/2) * 80, "=", 40, sq, units))}}}