Question 1154363
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Let W be the width (in meters).

Then the length is 4W.


The Pythagorean equation for the diagonal is


    W^2 + (4W)^2 = 150^2,   or

    W^2 + 16W^2 = 22500,

    17W^2       = 22500

    W^2         = 22500/17 = 1323.529

    W = {{{sqrt(1323.529)}}} = 36.38 meters.


So, the width is 36.38 meters;  Hence, the length is 4*36.38 = 145.52 meters.


By knowing dimensions, you can easily find the perimeter.
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Happy calculations (!)