Question 106639
Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.
Perpendicular lines have slope that are negative reciprocals.
So the slope of the new line= {{{1/3}}}
{{{(-5)=(1/3)(-0)+b}}}
{{{(y-5)=b}}}
y=5
{{{y=(1/3)x+5}}}
:)
{{{graph (300,300, -6,6,-6,6, -3x+1, (1/3)x+5)}}}