Question 1154102

The area of the rectangle is:

{{{A=L*W}}}

The perimeter of the rectangle is:

{{{P=2(L+W)}}}

if the perimeter of {{{62}}} cm 

{{{2(L+W)=62}}}

{{{L+W=62/2}}}

{{{L+W=31}}}.......eq.1

and if its length is {{{4}}} more than {{{twice}}} its width, we have

{{{L=2W+4}}}......eq.2

then

{{{2W+4+W=31}}}

{{{3W=31-4}}}

{{{3W=27}}}

{{{W=9cm}}}

go to eq.2, substitute {{{W}}}

{{{L=2*9+4}}}......eq.2

{{{L=22cm}}}


the area is {{{22cm*9cm=198cm^2}}}