Question 1154107


the length of a rectangle is {{{L=(x+5)}}} units and its width is {{{W=(x-3)}}} units.

Find the value of {{{x}}} if the perimeter is {{{40}}} units.


the perimeter is {{{2(L+W)=40}}}...simplify


{{{L+W=40/2}}}

{{{L+W=20}}}....substitute given length and width

{{{(x+5)+(x-3)=20}}}......solve for {{{x}}}

{{{x+5+x-3=20}}}

{{{2x+2=20}}}

{{{2x=20-2}}}

{{{2x=18}}}

{{{x=9}}}

=> the value of {{{x }}} is {{{9}}}

=> the length is {{{L=14}}} units and its width is {{{W=6}}} units