Question 106699

The sum of two numbers is {{{94}}}. 
let numbers be {{{x}}} and {{{y}}}, then:
{{{x+y = 94}}} 

if the second is {{{6}}} more than {{{3}}} times the first, we have:

{{{3x + 6 = y}}}

then, we can substitute this in equatation above:

{{{x + y = 94}}}

{{{x + 3x + 6 = 94}}}

{{{4x + 6 = 94}}}......add {{{-6}}} to both sides

{{{4x +6 -(6) = 94 - (6)}}}

{{{4x = 88}}} ..divide both sides by {{{4}}}

{{{x = 22}}}  ........ first number

{{{y = 3x + 6}}}

{{{y = 3*22 + 6}}}

{{{y = 66 + 6}}}

{{{y = 72}}}

check:

{{{22 + 72 = 94}}}

{{{94 = 94}}}