Question 1154100


A rectangular parking lot has a perimeter of {{{874}}}:

{{{2(L+W)=874}}}

{{{L+W=874/2}}}

{{{L+W=437}}}......eq.1

if the length {{{L}}} is {{{8}}} more then {{{twice}}} the width {{{W}}}, we have

{{{L=2W+8}}} .....eq.2, substitute it in eq.1


{{{2W+8+W=437}}}......eq.1

{{{3W=437-8}}}

{{{3W=429}}}

{{{W=429/3}}}

{{{highlight(W=143)}}}


go back to eq.2


{{{L=2W+8}}} .....eq.2, substitute {{{W}}}


{{{L=2*143+8}}} 

{{{L=286+8}}} 

{{{highlight(L=294)}}} 



 the dimensions of the rectangle are {{{highlight(294)}}} by {{{highlight(143)}}}