Question 106680
Factor:
{{{3x^3+7x^2-6x}}} First, factor an x from each term.
{{{x(3x^2+7x-6)}}} now factor the trinomial inside the parentheses.
{{{x(3x-2)(x+3)}}} To find the zero, set this equal to 0 and apply the zero products principle.
{{{x(3x-2)(x+3) = 0}}} {{{x = 0}}}
{{{3x-2 = 0}}} so {{{3x = 2}}} and {{{x = 2/3}}}
{{{x+3 = 0}}} so {{{x = -3}}}
The zeros are:
{{{x = 0}}}
{{{x = 2/3}}}
{{{x = -3}}}