Question 1153992


{{{P(x)=0}}} has the given roots {{{5-3i}}}=> complex roots always come in pairs, so you also have {{{5+3i}}}

{{{P(x)=(x-x[1])(x-x[2])}}}

{{{P(x)=(x-(5-3i))(x-(5+3i))}}}

{{{P(x)=(x-5+3i)(x-5-3i)}}}

{{{P(x)=x^2 - 10x + 34}}}