Question 1153880
{{{(x-6)^2+(y-3)^2=(-6-6)^2+(-1-3)^2}}}

Do what you can from that.




---MORE DETAIL----

Basic equation for circle in coordinate plane:  {{{(x-h)^2+(y-k)^2=r^2}}}

r is the radius.
point (h,k) is center point of circle.


Your given center is  (6,3).
Point on circle is given as (-6,-1).


Left member of equation you want is  {{{(x-6)^2+(y-3)^2}}}.
Use the given point ON the circle to find the value of {{{r^2}}}, the right member of the equation.


{{{(x-6)^2+(y-3)^2=(-6-6)^2+(-1-3)^2}}}
AND DO THE NECESSARY COMPUTATION to get this value for {{{r^2}}};
{{{(-12)^2+(-4)^2}}}
{{{144+16}}}
{{{160}}}


Finished equation is  {{{highlight((x-6)^2+(y-3)^2=160)}}}.