Question 1153869
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Thanks for saying what you did on the problem... but I don't understand it.<br>
The remainder when a polynomial f(x) is divided by (x-a) is equal to f(a).<br>
The remainder when the given polynomial is divided by (x+2) (that is, (x-(-2)) is f(-2):<br>
{{{(-2)^3+3(-2)^2+k(-2)-4 = -8+12-2k-4 = -2k}}}<br>
The remainder when the given polynomial is divided by (x-2) is f(2):<br>
{{{(2)^3+3(2)^2+k(2)-4 = 8+12+2k-4 = 2k+16}}}<br>
The first remainder is 3 times the second:<br>
{{{-2k = 3(2k+16)}}}<br>
Finish from there with basic algebra....<br>