Question 1153837


the equation in slope intercept form of the line:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

if the line passes through the points ({{{-4}}},{{{2}}}) and ({{{12}}},{{{6}}}), use them to find a slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(6-2)/(12-(-4))}}}

{{{m=4/(12+4)}}}

{{{m=4/16}}}

{{{m=1/4}}}


so far, we have

{{{y=(1/4)x+b}}} ..............use one point to calculate {{{b}}}

{{{6=(1/4)12+b}}}

{{{6=3+b}}}

{{{b=6-3}}}

{{{b=3}}}

and, your equation is:{{{y=(1/4)x+3}}}


{{{drawing ( 600, 600, -15,15, -15, 15, 
circle(12,6,.12),circle(-4,2,.12),locate(12,6,p(12,6)),locate(-4,2,p(-4,2)),
graph( 600, 600, -15,15, -15, 15, (1/4)x+3)) }}}