Question 1153822
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<pre>

Of 36 elements of the sample space, there are 6 doubles 


    (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)


and 2 separate outcomes (5,6) and (6,5) for a total of 11.


Therefore, the probability under the problem's question is


    P = {{{(6+2)/36}}} = {{{8/36}}} = {{{2/9}}}.   <U>ANSWER</U>
</pre>

Solved.


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If you want to learn this subject and this class of problems &nbsp;BETTER, &nbsp;DEEPER &nbsp;and &nbsp;WIDER, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Rolling-a-pair-of-fair-dice.lesson>Rolling a pair of fair dice</A> 

in this site. &nbsp;You will find there many other similar solved problems.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Solved problems on Probability</U>". 



Save the link to this textbook together with its description


Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson


into your archive and use when it is needed.