Question 1153817


A line in the coordinate plane has a slope of {{{m=4}}}, and a distance of {{{1}}} unit from the origin. => that is a point ({{{1}}},{{{0}}})

so, the equation of this line will be:

{{{y-y[1]=m(x-x[1])}}}...plug in given data

{{{y-0=4(x-1)}}}

{{{y=4x-4}}}

now we know {{{y}}}intercept is at  ({{{0}}},{{{-4}}})

Find the area of the triangle determined by the line and the coordinate axes


the triangle determined by the line and the coordinate axes is right triangle, and its legs are base and altitude

base is {{{1}}} unit long, altitude is {{{4}}}units long

=> {{{A=(1/2)*1*4}}}=> {{{A=2}}}



{{{ graph( 600, 600, -10, 10, -10, 10,4x-4) }}}