Question 1153768
<br><pre>
                       number of ways to get desired outcome
P(desired outcome) = ------------------------------------------
                     number of ways to choose 3 of the 14 chips</pre><br>
In every case the denominator of the fraction is<br>
{{{C(14,3) = 364}}}<br>
a. the chips are all different colors<br>
We need to choose 1 of the 6 red AND 1 of the 5 blue AND 1 of the 3 white:<br>
{{{C(6,1)*C(5,1)*C(3,1) = 6*5*3 = 90}}}<br>
P(all different colors) = 90/364<br>
b. the chips are all red<br>
We need to choose 3 of the 6 red AND 0 of the 5 blue AND 0 of the 3 white:<br>
{{{C(6,3)*C(5,0)*C(3,0) = 20*1*1 = 20}}}<br>
P(all 3 red) = 20/364<br>
c. 2 of the 3 are blue<br>
We need to choose 2 of the 5 blue and 1 of the 9 red or white:<br>
{{{C(5,2)*C(9,1) = 10*9 = 90}}}<br>
P(2 blue) = 90/364<br>
Simplify the fractions, or convert to decimals, if required....<br>