Question 1153791
The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?
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since the intercepts are given, it's
-2x + 6y = -2*6 = -12
x - 3y = 6 is the simplest.
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The long way:
find the slope m
m = diffy/diffx = 2/6 = 1/3
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y - y1 = m*(x - x1) where (x1,y1) is either point.
y - 0 = (1/3)*(x - 6)
{{{y = x/3 - 2}}}
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Also:
<pre>

|x   y   1|
|0  -2   1| = 0
|6   0   1|

</pre>

x*(-2*1 - 0*1) - y*(0*1 - 6*1) + 1*(0*0 - 6*-2) = 0
-2x + 6y + 12 = 0
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Several methods, several results, all equivalent.