Question 1153703

from the graph:

A ({{{8}}},{{{4}}})
B({{{2}}},{{{12}}})
C({{{12}}},{{{36}}})
D({{{36}}},{{{36}}})
E({{{26}}},{{{10}}})

the length of each side is equal to distance between its endpoints

{{{AB=sqrt((2-8)^2+(12-4)^2)=sqrt(36+64)=sqrt(100)=10}}}
{{{BC=sqrt((12-2)^2+(36-12)^2)=sqrt(100+576)=sqrt(676)=26}}}
{{{CD=sqrt((36-12)^2+(36-36)^2)=sqrt(576)=24}}}
{{{DE=sqrt((36-26)^2+(36-10)^2)=sqrt(100+676)=27.86}}}
{{{EA=sqrt((26-8)^2+(10-4)^2)=sqrt(324+36)=18.97}}}

add all lengths together:

{{{10+26+24+27.86+18.97=106.83=107}}}

  she need {{{107}}} feet of fencing