Question 1153682
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How much of a 60% orange juice drink must be mixed with 14 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice?
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v gallons of 60%


{{{60v+20*14=50(v+14)}}}----------solve for v.

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{{{60v+20*14=50v+50*14}}}
{{{60v-50v=50*14-20*14}}}

{{{v(60-50)=14(50-20)}}}

{{{v=14((50-20)/(60-50))}}}

{{{v=14*3}}}

{{{highlight(v=42)}}}