Question 1153657


A total of ${{{7000}}} is invested: 

part {{{x}}} at {{{6}}}% and the remainder {{{7000-x}}} at {{{10}}}%. How much is invested at each rate if the annual interest is ${{{470}}}?

{{{0.06x+0.10(7000-x)=470}}}

{{{0.06x+700-0.10x=470}}}

{{{0.06x-0.10x=470-700}}}

{{{-0.04x=-230}}}

{{{x=-230/-0.04}}}

{{{x=5750}}}->invested at each {{{6}}}% rate

then, other part is: 

{{{7000-x=7000-5750=1250}}}->invested at each {{{10}}}% rate


check:

{{{0.06*5750+0.10*1250=345+125=470}}}