Question 1153662
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<pre>

Let x be the part invested at  5%.


Then the amount invested at 2% is (14600-x) dollars.


The 5% investment produces the interest of 0.05x dollars.


The 2% investment produces the interest of 0.02*(14600-x) dollars.


The condition says


    0.05x - 0.02(14600-x) = 479.


Express x and calculate


    x = {{{(479 + 0.02*14600)/(0.05+0.02)}}} = 11014.29.


<U>ANSWER</U>.  $11014.29 was invested at 5%.  The rest,  (14600-11014.20) = 3585.71 dollars were invested at 2%.


<U>CHECK</U>.  0.05*11014.29 - 0.02*3585.71 = 479.00  dollars.   ! Precisely correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.