Question 1153632
Find the value of x for which the tangent line to {{{y=2x^2 + 1}}} will be parallel to the tangent line to {{{y = 4ln(x) - 3}}}?
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Slope of {{{y=2x^2 + 1}}} = 4x.
Slope of {{{y = 4ln(x) - 3}}} = 4/x
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4x = 4/x
x = 1
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The 2 slopes are 4 so they're parallel.
There are an infinite # of other slopes tangent to the 2 curves that are parallel.
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Mathlover switched to {{{y = 4ln(x) + 3}}}
Maybe that's what you meant?
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I'm not blind, but I do use reading glasses.
IDK how I was supposed to spot the alleged plagiarism, but I'm not overly worried about that.
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What I find interesting is that only x = 1 is a solution algebraically, but there are an infinite # of other lines that are parallel to the 2 graphs.