Question 1153601
<br>
Given vertices at (-5,0) and (5,0), the standard form of the equation is<br>
{{{x^2/5^2 - y^2/b^2 = 1}}}<br>
Plug in the coordinates of the other given point to determine b^2 to finish the problem.<br>
{{{6^2/5^2 - 11^2/b^2 = 1}}}
{{{36/25 - 121/b^2 = 1}}}
{{{121/b^2 = 36/25-1 = 11/25}}}
{{{b^2 = 275}}}<br>
The equation is<br>
{{{x^2/25 - y^2/275 = 1}}}<br>
A graph....<br>
{{{graph(600,400,-10,10,-20,20,sqrt(275(x^2/25-1)),-sqrt(275(x^2/25-1)))}}}<br>