Question 1153583
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The layout of the backyard lot is rectangular with a perimeter of 584 feet.
The width is 16 feet longer than half the length. Determine the​ backyard's dimensions. 
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L for length
(L/2)+16 for width


{{{2L+2(L/2+16)=584}}}

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{{{2L+L+32=584}}}

{{{3L=584-32}}}

{{{3L=552}}}

{{{L=552/3}}}

{{{highlight(L=184)}}}----------length
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{{{184/2+16=highlight(108)}}}---------width