Question 1153572
Notice the spaces added between your use of 'angle' symbol and character which follows them.  Without each space, the problem description was not being fully displayed.


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In right triangle ABC, AC = BC and < C = 90. Let P and Q be points on hypotenuse AB , such that < PCQ = 45. Show that AP^2+BQ^2=PQ^2. I think the first step is to rotate it 90 degrees counter clockwise around C, let P go to P’ and find < P’CQ. 
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