Question 1153545
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{{{graph( 330, 330, -5, 5, -2, 2,
          e^(-x^2)
)}}}


       Plot y = e^(-x^2)



From the plot, you can see that  e^(-x^2)  is an even function (which is very clear from the formula).


First derivative is  -2x*e^(-x^2), and when you equate it to zero, you easily will find the critical point x= 0. 
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