Question 1153483

An American football field is a {{{rectangle}}} with a perimeter of {{{1040ft}}}.

 the perimeter of a {{{rectangle}}} is:

{{{P=2(L+W)}}}....if {{{P=1040ft}}}

{{{2(L+W)=1040ft}}}

{{{L+W=1040ft/2}}}

{{{L+W=520ft}}}........eq.1


if the length is {{{200ft}}}{{{ more}}} than the width, we have

{{{L=W+200ft}}}........eq.2

go to 

{{{L+W=520ft}}}........eq.1, substitute {{{L}}}

{{{W+200ft+W=520ft}}}........solve for {{{W}}}

{{{2W=520ft-200ft}}}

{{{2W=320ft}}}

{{{W=320ft/2}}}

{{{W=160ft}}}


go to

{{{L=W+200ft}}}........, substitute {{{W}}}

{{{L=160ft+200ft}}}

{{{L=360ft}}}


answer: the width is {{{160ft}}} and length of the rectangular field is {{{360ft}}}