Question 106565
{{{x^3-9x=0}}}
this equation cannot be factored, because there is no square root of {{{x^3}}}




{{{y^2-2y-24=0}}}
GAME:  think of 2 numbers that is the product to the 3rd term (-24) and the sum of the 2nd term (-2).
These two numbers would be:  -6,4
This is because: {{{-6*4=-24}}}
And: {{{-6+4=-2}}}

now, substitute these two numbers as the middle term in the equation:
{{{y^2-6y+4y-24=0}}}

Now, common factor by GROUPING
-Common Factor the first two terms
-Common factor of {{{y^2-6y}}} is y
-Common Factor the last two terms
-Common factor of {{{4y-24}}} is 4

Therefore, the equation is now {{{y(y-6)+4(y-6)=0}}} after dividing by the common factors.

Take the equation {{{y(y-6)+4(y-6)=0}}} and common factor again, this time the common factor being (y-6)

Therefore, {{{(y-6)*(y-4)=0}}}