Question 1153471
<br>
There are n factors of (2x^3-1/x).<br>
To get a constant partial product, you need to pick the "-1/x" term 3 times as often as you pick the "2x^3" term.<br>
That means the number of factors must be a multiple of 4.<br>
ANSWER: The exponent n can be any positive multiple of 4.<br>
Example 1: n=4<br>
The next-to-last term in the expansion is<br>
{{{C(4,1)((2x^3)^1)(-1/x)^3 = (4)(2x^3)(-1/x^3) = -8}}}<br>
Example 2: n=8<br>
The second from last term in the expansion is<br>
{{{C(8,2)((2x^3)^2)(-1/x)^6 = (28)(4x^6)(1/x^6) = 112}}}<br>