Question 1153462
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<pre>

22800 = {{{9900*e^(0.04*t)}}}.


In this equation t is the unknown time in years.


{{{22800/9900}}} = {{{e^(0.04*t)}}}


2.3030 = {{{e^(0.04*t)}}}


Take the natural logarithm of both sides


ln(2.3030) = 0.04*t


t = {{{ln((2.3030))/0.04}}} = 20.855.


<U>ANSWER</U>.  In 20.885 years.
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Solved.