Question 1153419
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Use the binomial probability distribution to solve this problem.



Probability  P(2 heads and 2 tails in 4 flipping) = {{{C[4]^2 * 0.62^2 * (1-0.62)^(4-2)}}}, where {{{C[2]^2}}} = {{{4! / (2! * (4-2)!)}}}.


             P(2 heads and 2 tails in 4 flipping) = {{{((4*3)/2) * (0.62)^2 * 0.38^2}}} = 0.333044 = 33.044%.    <U>ANSWER</U>
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