Question 1153289
The area of the circle is 201 cm^2, and that gives a radius of 8 cm. 
Draw this,  making the chord parallel to the diameter. The distance to the chord is 3 cm and forms a right triangle with sides 3, 8 (the hypotenuse), so the other side, half the chord is sqrt(55) cm.

The central angle is cos ^(-1) 3/8 or 67.98 degrees, call it 68 degrees.

the area of the segment containing the chord and the two triangles formed by the perpendicular is 201*136/360 or 75.93 cm^2.  But, the two triangles are not part of that area, for they are on the wrong side of the segment.

the area of each is 1/2 bh or 3 sqrt(55)/2, but both together make 3 sqrt(55)

subtract 3 sqrt(55) from the 75.93 to get 53.69 cm^2.
B