Question 1153290
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<pre>

Find the area A of one circle of the radius of 9 meters.


Then double it to get 2A.


Then take {{{2A - (2/6)A}}} = {{{2A - (1/3)A}}} = {{{(5/3)*A}}}.


Then add to it the area of two equilateral triangles with the side length of 9 meters.


In this way, you will get the answer.
</pre>

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If you need more details and explanations, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Surface-area/Area-of-a-segment-of-the-circle.lesson>Area of a segment of the circle</A>

in this site, <U>Problem 2</U>.