Question 1153296
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The outer radius of the pipe is  R = 9.40 cm.


The interior radius of the pipe is the apothem of the regular hexagon, so its length is  r = {{{9.4*sqrt(3)/2}}} = 8.14 cm.


The cross-sectional are is the difference of the area of the bigger and smaller circles


    {{{pi*R^2}}} - {{{pi*r^2}}} = {{{3.14159*(9.4^2-8.14^2)}}} = 69.43 cm^2.
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