Question 106536
(2/3x^2 + 1/5x + 1/6) + (1/2x^2 - 1/3x + 2/3)
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= (1/30)(20x^2 + 6x + 5) + (1/6)(3x^2 -2x + 4)

= (1/30)(20x^2 + 6x + 5) + (5/30)(3x^2 -2x + 4)

= (1/30)[20x^2 + 6x + 5) + (5)(3x^2 -2x + 4)]

= (1/30)[35x^2-4x+25]

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Cheers,
Stan H.