Question 1153238
A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)
<pre><b><u>Algebra:</b></u>        With number being N, equation to be solved: {{{matrix(1,3, N + N/5 + N/6, "=", 82)}}}
<b><u>Pre-Algebra:</b></u>   {{{matrix(1,5, (1/5) + (1/6), "=", (6/30) + (5/30), "=", 11/30)}}} 
                The number, with the same denominator as the above fraction, is represented by 1, or fraction {{{30/30)
                We now get {{{matrix(1,3, (11/30) + (30/30), "=", 41/30)}}}  
                We now see that: {{{matrix(1,8, (11/30) + (30/30), or, (41/30), of, a, number, "=", 82)}}}, and so, the number MUST BE: {{{highlight_green(matrix(1,7, 82/(41/30), "=", 82 * (30/41), "=", 2cross(82) * (30/cross(41)), "=", 60))}}}
<b><u>IGNORE the OTHER PERSON'S RESPONSE, as it is SENSELESS!!</b></u>